Q46. What is the equation of a circle that has diameters on the lines 2x - 3y - 5 = 0 and 3x - 4y = 7, and a radius of 8?Mathematics — NUST Mock 10 — Question 46 of 200A. x2 + y2 + 4x - 4y + 56 = 0B. x2 + y2 - 2x + 2y - 62 = 0C. x2 + y2 - 3x - 3y + 36 = 0D. x2 + y2 + 6x + 6y - 42 = 0Practice more Mathematics MCQs for entrance exam preparation on Examora.io.← Previous Question Next Question →