Q21. Two identical metal plates show photoelectric effect. Light of wavelength λA falls on plate A and λ B falls on plate B. λA = 2λ B. The maximum K.E. of the photoelectrons are KA and KB respectively. Which one of the following is true?Physics — Dawn of Modern Physics — Question 21 of 217A. 2KA = KBB. KA = 2KBC. KA < KB/2D. KA > 2KBPractice more Physics MCQs for entrance exam preparation on Examora.io.← Previous Question Next Question →