Q15. What is the equation of a circle with its center at (5, -2) and a radius of 4?Mathematics — Conic Sections — Question 15 of 272A. x2 + y2 - 10x + 4y + 13 = 0B. x2 + y2 - 10x + 4y - 13 = 0C. x2 + y2 + 10x + 4y + 13 = 0D. x2 + y2 - 10x - 4y + 13 = 0Practice more Mathematics MCQs for entrance exam preparation on Examora.io.← Previous Question Next Question →