Q134. What is the equation of the circle with radius 3 that lies in the fourth quadrant and is tangent to the lines x = 0 and y = 0?Mathematics — Conic Sections — Question 134 of 272A. x2 + y2 - 6x - 6y + 9 = 0B. x2 + y2 - 6x + 6y + 9 = 0C. x2 + y2 + 6x - 6y + 9 = 0D. x2 + y2 + 6x + 6y + 9 = 0Practice more Mathematics MCQs for entrance exam preparation on Examora.io.← Previous Question Next Question →